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How do I apply the change of base formula to y=log (sub 3) x
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How do I apply the change of base formula to y=log (sub 3) x

User Sachin Dobariya
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y=\log_3x \Leftrightarrow y=(\log_cx)/(\log_c3)\text{ where } c\in \mathbb{R}_+\setminus\{1\}
User Itay
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