Question

A rectangular tabletop has a length of 4 3/4 feet and an area of 11 7/8 square feet. What is the width of the tabletop

Answer 1

A=B*H where B=base, H=height and A=area
area= 11 and 7/8
B= 4 and 3/4
let H= x
11 and 7/8=4 and 3/4 *x
x= (11 and 7/8) / (4 and 3/4)
x= 5/2

Therefore the width of the tabletop is 2.5 feet

Answer 2

First I would turn the mixed fractions into improper fractions so it will be easier division. That would make 4 3/4 become 19/4 and 11 7/8 become 95/8. Next, the formula for area is length x width= area. If you plug in the numbers, it will become 19/4x=95/8, x being the width. You would divide 95/8 by 19/4 and end up with 5/2 or 2 1/2.