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What is the equation of a line that passes through the point (1, -10) and is perpendicular to the equation y

What is the equation of a line that passes through the point (1, -10) and is perpendicular-example-1
User Kyle Pittman
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1 Answer

12 votes
12 votes

The equation of a line in the slope intercept form is expressed as

y = mx + c

Where

m represents slope

c represents y intercept

The given equation is expressed as

y = - x/3 + 5

By comparing with the slope intercept equation,

slope, m = - 1/3

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line. The negative reciprocal of - 1/3 is 3. Thus, the slope of the line passing through the point, (1, - 10) is 3

We would determine the y intercept, c by substituting x = 1, y = - 10 and m = 3 into the slope intercept equation. It becomes

- 10 = 3 * 1 + c

- 10 = 3 + c

c = - 10 - 3

c = - 13

We would substitute m = 3 and c = - 13 into the slope intercept equation. Thus, the equation of the line is

y = 3x - 13

Option D is correct

User Kreeszh
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