Question

What is the surface area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a length of 48 in? A. 529.86 in2 B. 256.22 in2 C. 950.02 in2 D. 849.73 in2

Answer 1

Answer: Option 'C' is correct.

Explanation:

Since we have given that

Diameter of cylinder = 6.3 inches

Radius of cylinder is given by

`(6.3)/(2)\ in`

Height of cylinder = 48 in.

As we know the "Surface area of cylinder":

`Area=2\pi rh\\\\Area=2* (22)/(7)* (6.3)/(2)* 48\\\\Area=950.02\ in^2`

Hence, Option 'C' is correct.

Answer 2

The surface area of the cylindrical ring is given by
πdh
where d is the diameter and h is the height:
π•6.3•48 = 950.02
The answer is C. 950.02 in^2