Answer:
Option D is correct
Explanations:
The model equation for the height of the ball at time t is given as:
h(t) = - 16t² + 30t + 6
Note:
The ball reaches a maximum height at a time when dh/dt = 0
The height of the ball at any time t is given by h(t) = - 16t² + 30t + 6
From h(t), dh/dt will be calculated as:
dh/dt = -32t + 30
At maximum height, dh/dt = 0
0 = -32t + 30
32t = 30
t = 30/32
t = 0.94 s
Therefore, the ball reaches the maximum height at 0.94 second
Let us find the position of the ball at t = 2 seconds
h(t) = - 16t² + 30t + 6
h(2) = -16(2)² + 30(2) + 6
h(2) = -64 + 60 + 6
h(2) = 2
At t = 2 seconds, the height of the ball is 2 feet
Let us find the position of the ball at t = 1.5 seconds
h(t) = - 16t² + 30t + 6
h(1.5) = -16(1.5)² + 30(1.5) + 6
h(1.5) = -36 + 45 + 6
h(1.5) = 15
At 1.5 seconds, the ball is 15 feet high
Since the height of the ball, h(t) is a function of time, the ball can clear the fence depending on the time, t, spent in the air