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30 votes
30 votes
Describe the Method and Operation

User Ibolit
by
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1 Answer

21 votes
21 votes

\text{Answer: 5n}^8m^6

Given that


\begin{gathered} ((5n^6)/(m^(-3)n^2))^2 \\ \text{According to the law of indies,} \\ ((a)/(b))^2\text{ = }((a)^2)/((b)^2) \\ ((5n^6)/(m^(-3)n^2))\text{ = }((5n^6)^2)/((m^(-3)n^2)^2) \\ \text{According to the law of indicies again,} \\ (a^x)^y=a^(x\cdot y) \\ =\text{ }\frac{(5n^{6\text{ x 2}})}{(m^(-3\cdot2)n^(2\cdot2))} \\ =\text{ }(5n^(12))/((m^(-6)n^4)) \\ \text{According to the law of indices} \\ x^(-1)\text{ = }(1)/(x) \\ =5^{}n^(12)\cdot n^(-4)\cdot m^6 \\ =5n^{12\text{ - 4}}m^6 \\ =5n^8m^6 \end{gathered}

User Chaqke
by
2.8k points
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