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27 votes
Determine the range of y=2/(2x+1)

User Acconrad
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1 Answer

19 votes
19 votes

To solve this question we will solve the given equation for y and we will analyze the possible values of y (that will be the range of the given function).

Assuming that 2x+1≠0, and multiplying the given equation by 2x+1 we get:


\begin{gathered} y\cdot(2x+1)=(2)/(2x+1)\cdot(2x+1), \\ 2yx+y=2. \end{gathered}

Subtracting y from the above equation we get:


\begin{gathered} 2yx+y-y=2-y, \\ 2yx=2-y\text{.} \end{gathered}

Dividing the above equation by 2y we get:


\begin{gathered} (2yx)/(2y)=(2-y)/(2y), \\ x=(2-y)/(2y) \end{gathered}

Therefore, y can be all real numbers except zero.

Answer:


(-\infty,0)\cup(0,\infty)\text{.}

User Dacopenhagen
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