Question

Can I help with this problem. If z varies inversely as w^2 and z = 10 when w = 2. Find z when w = 6

Answer 1

First, we need the find the value of the constant k:

`z=(k)/(w^2)`

Then, we use the given values to find k. Therefore:

z = 10 when w = 2

`10=(k)/(2^2)`

And solve for k:

`\begin{gathered} 10=(k)/(4) \\ 10\cdot4=4\cdot(k)/(4) \\ k=40 \end{gathered}`

Now, when w = 6, z will be:

`z=(k)/(w^2)=(40)/(6^2)=(40)/(36)=(10)/(9)`

Answer:

`z=(10)/(9)`