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Equation match a.) m= -2/3, b=3b.) m = -3/2, (4,-1)

User Oscar Corona
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1 Answer

12 votes
12 votes

Given:

A.)

Slope of the line (m) = -2/3

Y-intercept (b) = 3

The given can be used to make an equation under the Slope-Intercept Form:


\text{ y = mx + b}

By substituting m and b to y = mx + b, we can generate the equation.

We get,


\text{ y = mx + b}
\text{ y = (-2/3)x + (3)}
\text{ y = -}(2)/(3)x\text{ + 3}
3(\text{ y = -}(2)/(3)x\text{ + 3)}
3y\text{ = -2x + 9}
2x\text{ + 3y = 9}

Therefore, the equation match to m = -2/3 and b = 3 is 2x + 3y = 9.

B.)

Slope of the line (m) = -3/2

x,y = 4,-1

To be able to generate the equation, let's first determine the y-intercept (b). We can get it by substituting m = -3/2 and x,y = 4,-1 to the equation y = mx + b.

We get,


\text{ y = mx + b}
\text{ -1= (-3/2)(4) + b}
-1\text{ = }(-12)/(2)\text{ + b }\rightarrow\text{ -1 = -6 + b}
\text{ b = -1 + 6}
\text{ b = 5}

Since we now found that the y-intercept (b) = 5, let's substitute b and m = -3/2 to y = mx + b to generate the equation.

We get,


\text{ y = mx + b}
\text{ y = (-3/2)x + (5)}
\text{ y = -}(3)/(2)x\text{ + 5}
\text{ -2(y = -}(3)/(2)x\text{ + 5)}
\text{ -2y = 3x - 10}

Therefore, the equation that match m = -3/2 and (4,-1) is -2y = 3x - 10.

User Zeynep
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