Question

20 ping pong balls are numbered 1-20, with no repetition of any of the numbers. What is the probability of selecting one ball that is either odd or a number 4 ball?Need answer as a percentage amountMy choices are: 50, 5, 45, or 55

Answer 1

The answer in percentage is %55

The total amount of balls is 20. Half of them are odd, but also we need to add the probability of picking the 4.

Then,

`\begin{gathered} 20\cdot(1)/(2)=10 \\ 10+1=11 \end{gathered}`

So of the 20 possible outcomes, we want to know the probablity of 11 of them. That's a probability of 11/20. Thus,

11/20 = 0.55

To convert the result in percentage, we multiply by 100:

0.55 * 100 = %55