Question

2v2 -5v +3 = 0 how did I do this?

Answer 1

`2v2 -5v +3 = 0 \\ \\\Delta = b^(2)-4ac = (-5)^(2)-4*2*3= 25-24=1\\ \\v_(1)=(-b-√(\Delta ))/(2a) =(5- √(1 ))/(2*2)=(5- 1)/(4)= (4)/(4)=1\\ \\v_(2)=(-b+√(\Delta ))/(2a) =(5+ √(1 ))/(2*2)=(5+1)/(4)= (6)/(4)=(3)/(2)=1(1)/(2)`