Question

A roller coaster starts at rest from a height of 110m, and accelerates down the track to a height of 10m. Find the speed it can reach, assuming no friction.

Answer 1

`v^(2)` =
`u^(2)` + 2ar

`v^(2)` = 0 + 2 * 9.8 m/s * (110 m - 10m)
v =
`√(1960)` = 44 m/s
if it is going down vertically. if there is some angle - it would be another story

Answer 2

Answer: The final velocity of the roller coaster is 44.3 m/s

Step-by-step explanation:

To calculate the final velocity of the roller coaster, we use third equation of motion:

`v^2-u^2=2as`

where,

s = distance traveled = 110 - 10 = 100 m

u = initial velocity of the roller coaster = 0 m/s

v = final velocity of the roller coaster = ? m/s

a = acceleration due to gravity =
`9.8m/s^2`

Putting values in above equation, we get:

`v^2-(0)^2=2* 9.8* 100\\\\v=√(1960)=44.3m/s`

Hence, the final velocity of the roller coaster is 44.3 m/s