Question

Solve the system using the method of elimination by addition

Answer 1

Given:

There are given the two systems of the equation:

`\begin{gathered} (3)/(5)x+(2)/(3)y=1...(1) \\ 18x+20y=30...(2) \end{gathered}`

Step-by-step explanation:

According to the question:

We need to solve the equation by using the elimination method.

So,

To solve the above equation, we need to perform the elimination method.

So,

`\begin{gathered} 18((3)/(5)x+(2)/(3)y=1)=((54)/(5)x+12y=18)...(3) \\ (3)/(5)(18x+20y=30)=((54)/(5)x+12y=18)...(4) \end{gathered}`

Then,

We need to subtract equation (3) from equation(4):

Then,

`\begin{gathered} ((54)/(5)x+12y=18)-((54)/(5)x+12y=18) \\ 0 \end{gathered}`

Final answer:

Hence, the solution is 0.