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a 2-kg metal ball moving at a speed of 3 m/s strikes a 1-kg wooden ball that is at rest. after the collision, the speed of the metal ball is 1 m/s. Assuming momentum is conserved, what is the speed of the wooden ball

1 Answer

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m1u1 + m2u2 = m1v1 + m2v2
2 * 3 + 1 * 0 = 2 * 1 + 1 * v2
6 = 2 + v2
v2 = 6 - 2 = 4 m/s.

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