For this case we have that the following function complies with the given conditions:
To prove it, let's find the roots of the polynomial:
By doing common factor 3 we have:
Factoring the second degree polynomial we have:
Then, the solutions are:
Solution 1:
Solution 2:
Answer:
A second degree polynomial function f (x) that has a lead coefficient of 3 and roots 4 and 1 is:
