Question

Complete these equations for the ionization of an Arrhenius acid or base in water. Include the states of the products.

1.) HI(aq)
2.) LiOH(s)

Answer 1

The ionization for HI in water is HI(aq) → H+(aq) + I−(aq), and for LiOH, it is LiOH(s) → Li+(aq) + OH−(aq). These equations depict the release of ions by an Arrhenius acid and base when dissolved in water.

Step-by-step explanation:

The question is asking to complete the ionization equations for an Arrhenius acid and base when they dissolve in water. For the acid HI, and the base LiOH, the equations would be:

1. HI(aq) → H+(aq) + I−(aq)

2. LiOH(s) → Li+(aq) + OH−(aq)

Arrhenius acids release hydrogen ions (H+) when they ionize in water, while Arrhenius bases release hydroxide ions (OH−). These equations represent the substances splitting into their ions in an aqueous solution.

Answer 2

1)
HI(aq) → H⁺(aq) + I⁻(aq)
So this is an Arrhenius acid because it releases H⁺.

2)
LiOH(s) → Li⁺ + OH⁻
So this is an Arrhenius base because it releases OH⁻