Question

A circular loop of wire with a diameter of 25.935 cm is in the horizontal plane and carries a current of 14.171 A counterclockwise, as viewed from above. What is the magnetic field, in microTeslas, at the center of the loop?

Answer 1

Answer tab

First, for us to have a better understanding, let us draw the situation:

The magnetic field in the middle of a single coil is given by:

`B=(\mu_0i)/(2R)`

Replacing our values, we get:

`B=(4\pi *10^(-7)*14.171)/(25.935*10^(-2))=68.66\mu T`

Thus, our answer is B=68.66uT