2 Answers

Ihor Klimov · Answer 1 · 2017-07-10T03:41:01+0000

Answer:

$x = \log_b y$

Explanation:

Using logarithmic rules:

$\log a^x = x \log a$

$(\log x)/(\log b) = \log_b x$

Given the equation:

y = b^x

Taking log both sides we have;

$\log y = \log b^x$

Apply the logarithmic rule:

$\log y = x \log b$

Divide both sides by log b we have;

$(\log y)/(\log b) = x$

Apply the logarithmic rule:

$\log_b y = x$

or

$x = \log_b y$

Therefore, the equation in logarithmic form is,
$x = \log_b y$

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