Question

True or false18. In the circle: x2+(y-2)2=12, the radius is 12

Answer 1

False

Step-by-step explanation

The equation of a circle is:

`(x-x_0)^2+(y-y_0)^2=r^2`

Where (x0, y0) is the center of the circle and r is the radius.

If we have the equation of a circle:

`x^2+(y-2)^2=12`

x0 = 0 and y0 = 2. Therefore the center of the circle is at point (0, 2). Also, we have that:

`r^2=12`

Solving for r, the radius of this circle is:

`r=\sqrt[]{12}`

Therefore, it is false that the radius of the given circle is 12.