Question

Solve for x: 3 − (2x − 5) < −4(x + 2)

x < −8

x > −8

x < −3

x > −3

I just need help because i don't know how i would do it with x on both sides

Answer 1

Answer:
`x<-8`

Explanation:

The given inequality :
`3-(2x-5)<-4(x+2)`

To solve the inequality for x , first we open the parenthesis , we get

`3-2x+5<-4x+(-4)2`

`\Rightarrow\ 3-2x+5<-4x-8` [Note : (-)(+)=(-)]

`\Rightarrow\ 3+5-2x<-4x-8`

`\Rightarrow\ 8-2x<-4x-8`

Add 4x on both sides , we get

`8-2x+4x<-4x-8+4x`

`8+2x<-8`

Subtract 8 from both sides , we get

`2x<-16`

Divide both sides by 2 , we get

`x<-8`

Hence, the correct answer is :
`x<-8`

Answer 2

The answer is x < −8

3 − (2x − 5) < −4(x + 2)
3 - 2x + 5 < -4x - 8
8 - 2x < -4x - 8
4x - 2x < -8 - 8
2x < -16
x < -8