Question

4. Which line is PERPENDICULAR to y = 2/3 x + 3*O y = - 2/3 x + 2O y = 2/3 x + 2y = -3/2 x + 2O y = 3x - 2/3O y = 3

Answer 1

We know that in order for a function to be perpendicular to another, it has to follow:

`m_2=-(1)/(m_1)`

Where m1 is the slope of a function and m2 is the slope of the function perpendicular to it. From this, we will have that the function perpendiculat to y = 2/3x +3 will be:

`y=-(3)/(2)x+2`