Question

If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same, the heat produced by the heater will be

a. reduced one-half.
c. two times the original heat.
b. unchanged.
d. four times the original heat.

Answer 1

Q=l^2 times R times t
Where Q - heat, I -current, R - resistance and t is time

If you increase I twice (and it's squared), than Q gonna went up 4 times (2 squared).

Choose last

Answer 2

Step-by-step explanation:

It is given that,

Current,
`I_1=6\ A`

Heat produced,
`H_1=I_1^2Rt`............(1)

Where

R is the resistance

t is the time taken

So,
`H_1=36Rt`

Current,
`I_2=12\ A`

Heat produced,
`H_1=I_2^2Rt`

So,
`H_2=144Rt`.............(2)

From equation (1) and (2), it is clear that

`H_2=4* H_1`

So, If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same, the heat produced by the heater will be four times the original heat.