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A testing chamber holds a 2.00 L sample of neon gas at 300.0 K. If the pressure is measured inside the chamber as 3.25 atm, how many moles of neon are present?____ mol Ne

User Vanburen
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1 Answer

14 votes
14 votes

Answer:

There are 0.26 moles of neon.

Step-by-step explanation:

From the information in the exercise we know that:

- Volume (V): 2.00L

- Temperature (T): 300.0K

- Pressure (P): 3.25atm

Using the Ideal Gases Law formula, we can calculate the number of moles (n), by replacing the values of V, T and P:


\begin{gathered} P*V=n*R*T \\ 3.25atm*2.00L=n*0.082(atm*L)/(mol*K)*300.0K \\ 6.5atm*L=n*24.6(atm*L)/(mol) \\ (6.5atm*L)/(24.6(atm*L)/(mol))=n \\ 0.26mol=n \end{gathered}

So, there are 0.26 moles of neon (0.3 rounded).

User Vjwilson
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