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What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = -1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = 1

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = 1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = -1

User Slbox
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(3 \pi )/(4) * (180degrees)/( \pi ) = 135 degrees.

Drawing a reference triangle, this is 45 degrees in the second quadrant.
See attached.

Sine theta will be opposite/hypotenuse

= (1)/( √(2) ) * ( √(2) )/( √(2) ) = ( √(2) )/(2)

Cosine will be adjacent/hypotenuse

(-1)/( √(2) ) * ( √(2) )/( √(2) ) = (- √(2) )/(2)

Tangent will be opposite/adjacent

(1)/(-1)=-1
What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians? sin Θ = square-example-1
User Fifigyuri
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