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Use trigonometric identities to solve tan(2θ)+tan(θ)=0 exactly for 0≤θ≤π.

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tan (2 \theta)+tan \theta = (2 tan \theta)/(1-tan^2 \theta) +tan \theta = 0
Multiplying equation by denominator gives:

2 tan \theta + tan \theta (1-tan^2 \theta) = 0
Factor out a tan

tan \theta (3-tan^2 \theta) = 0 \\ tan\theta = 0, \pm √(3)

\theta = 0, (\pi)/(3), (2\pi)/(3)
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