Question

Laws of exponent - divisionsimplify-8s⁴t____16st⁴

Answer 1

`(-8s^4t)/(16st^4)\text{ = }(-s^3)/(2t^3)`

Here, we want to divide the terms given in the question

We proceed as follows;

`(-8s^4t)/(16st^4)`

We pair up similar terms and multiply it by the rest

Kindly recall the law of indices which states the following;

`\frac{a^x}{a^y^{}\text{ }}=a^(x-y)`

Thus, we have that;

`\begin{gathered} (-8)/(16)*(s^4)/(s)*(t)/(t^4) \\ \\ =\text{ }(-1)/(2)\text{ }* s^3\text{ }*\text{ }(1)/(t^3) \\ \\ =\text{ }(-s^3)/(2t^3) \end{gathered}`