Question

Matthew found a deposit with a diameter that is 10^2 times as long as Josef's. How many millimeters long is the diameter of Matthew's deposit? Josefs deposited is 0.012.

Answer 1

The information we have about Josef's deposit is that is 0.012 milimeters.

We are told that Matthew's deposit is 10^2 times as long as Josef's.

What this means is that to find the length of the diameter of Matthew's deposit, we need to multiply 0.012 mm by 10^2:

`0.012*10^2`

to multiply a decimal number by a power of 10, we need to move the decimal point to the right, the number of times indicated by the power. In this case we need to move the decimal point 2 times to the right, and we get:

`0.012*10^2=1.2`

Answer:

How many millimeters long is the diameter of Matthew's deposit? 1.2mm