1 Answer

Tom Leek · Answer 1 · 2023-08-26T16:49:03+0000

Given that the mass of the jet is m = 20000 kg.

The tangential velocity of the jet is

$\begin{gathered} v=\frac{1500\operatorname{km}}{hr} \\ =(1500*1000)/(60*60) \\ =416.67\text{ m/s} \end{gathered}$

The centripetal acceleration is

$a=\text{ 5 g}$

This centripetal acceleration can be converted into m/s by using acceleration due to gravity, g = 9.8 m/s which is as follows

$\begin{gathered} a=(5)/(9.8) \\ =0.51\text{ m/s} \end{gathered}$

We have to find the radius, r.

It can be calculated as

$\begin{gathered} a=(mv^2)/(r) \\ r=(mv^2)/(a) \end{gathered}$

Substituting the values, the radius will be

$\begin{gathered} r=(20000*(416.67)^2)/(0.51) \\ =6.8083*10^9\text{ m} \\ =6.8083*10^6\text{ km} \end{gathered}$

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