Question

Find the equation of a line with given slope and containing the given point. Write the equation in slope-intercept form. Horizontal line containing (-5,5)

Answer 1

y = 5

Explanation:

Pre-Solving

We want to find the equation of a horizontal line that passes through (-5,5) in slope-intercept form.

Slope-intercept form is given as y=mx+b, where m is the slope and b is the value of y at the y-intercept.

Recall that a horizontal line has a slope of 0.

Solving

As we know that a horizontal line's slope is 0, we can plug that into the equation to find the line.

Substitute m with 0.

y = 0x + b

Now, we need to find b.

As the equation passes through (-5, 5), we can use its values to solve for b.

Substitute -5 as x and 5 as y.

5 = 0(-5) + b

Multiply.

5 = 0 + b

5 = b

Substitute 5 as b.

y = 0x + 5

This can be simplified to:

y = 5

Answer 2

If the line is horizontal then, the line would have the form y=c where c is constant value.

Given that the point contains the point (-5,5) we deduce that the constant value is 5.

Therefore, the equation would be y=5.