Question

Latoya, Josh, and Alonzo have a total of $82 in their wallets. Josh has 2 times what Alonzo has. Latoya has $6 less than Alonzo. How much does each have?Amount in Latoya's wallet:Amount in Josh's wallet:Amount in Alonzo's wallet:

Answer 1

As per given by the question,

There are given that Latoya, Josh, and Alonzo have a total of $82 in their wallets.

now,

Let L, J, and A be the amounts that each person has.

So,

`L+J+A=82\ldots\text{ (1)}`

Now,

According to the question,

Jos has 2 times what Alonzo has,

So,

`L+2A+A=82\ldots\text{. (2)}`

Now,

Latoya has $6 less than Alonzo,

So,

`(A-6)+2A+A=82_{}\ldots\ldots\text{.}(3)`

Then,

From the equation (3),

`\begin{gathered} (A-6)+2A+A=82 \\ A-6+3A=82 \\ 4A-6=82 \\ 4A=82+6 \\ 4A=88 \\ A=(88)/(4) \\ A=22 \end{gathered}`

Now,

From the question,

Jose has 2 times what Alonzo has,

So,

`\begin{gathered} A(\text{Alonzo)}=22 \\ J(\text{Jose)}=22*2 \\ =44 \end{gathered}`

Now,

Latoya has 6 less than Alonzo,

So,

`\begin{gathered} A=22 \\ L=22-6 \\ L=16 \end{gathered}`

Then,

From the equation (1).

`\begin{gathered} L+J+A=82 \\ 16+44+22=82 \\ 82=82. \end{gathered}`

Hence,

Amount in Latoya wallets is$16.

Amounts in Jose's wallets is $44.

Amount in Alonzo wallet's is $22.