Question

suppose a population is carrying a condition controlled by two alleles R (dominant) and r (recessive). if the frequency of the r allele is 15% and the frequency of the R allele is 85%. what will be the frequency of the RR genotype ,assuming evolution is not occuring?

Answer 1

I believe it's 72.25%

Answer 2

Frequency of the RR
`= 72.25`%

Step-by-step explanation:

Given -

R is the dominant allele and r is the recessive allele.

The frequency of the r allele is
`15`%
`= 0.15`

The frequency of the R allele is
`85`%
`= 0.85`

As per Hardy Weinberg's equation-

`p = 0.85`

`q = 0.15`

Also, evolution is not occurring is the basic assumption of Hardy Weinberg's principle.

Frequency of the RR genotype is equal to
`p^(2)`

Substituting the value of "p" we get

`p^(2) = 0.85^(2) \\= 0.7225\\= 72.25`