Question

2(t. A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6"C. Determine thetemperature at which the volume of the gas is 3.45 L.a) 309 K b) 281 K e) 20,6 K d) 294 K e) 326 K

Answer 1

They tell us that the pressure of the gas is constant and the temperature and volume vary. If we assume that the gas behaves like an ideal gas, we can apply Charles's law, which tells us:

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

V1 is the initial volume, 3.62L

T1 is the initial temperature, 21.6°C=294.75K

V2 is the final volume, 3.45L

T2 is the final temperature, in Kelvin

Now, we clear T2 and replace the known data:

`T_2=V_2*(T_1)/(V_1)`
`T_2=3.45L*(294.75K)/(3.62L)=281K`

The temperature at which the volume of the gas is 3.45 L will be 281K

Answer. b) 281K