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What does the value of f(x)=(1+1/x)^x approach as x approaches infinity?

User James Jacques
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1 Answer

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In order to determine the value of f(x) as x approaches to oo, replace larger values of x into the function and identify the tendency of f(x), as follow:

x = 1000


f(1000)=(1+(1)/(1000))^(1000)\approx2.7169

x = 1000000


f(1000000)=(1+(1)/(1000000))^(1000000)\approx2.7182

x=1000000000


f(1000000000)=(1+(1)/(1000000000))^(1000000000)\approx2.7182

As you can notice, as x approaches to oo, f(x) approaches to 2.7182..., which is the value of constant e.

answer: e

User Nisarg Bhavsar
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