Question

A 3.10-cm diameter coin is placed a distance of 25.0cm from a concave lens that has a focal length of -11.0 cm. Determine the image distance ad diameter of the image.Must follow GRESA format. Make sure to list the L-O-S-T Image formed accordingly Solution format:Given Required: Equation(s) Needed: Solution:(a) (b) Final Answer L-ocation: O-rientation: S-ize: T-ype:

Answer 1

Given

3.1 cm diameter coin

25 cm from the concave lens

11 cm focal lens

Procedure

Below is a sketch how the image is created using a concave lens:

Equation(s) Needed:

`\begin{gathered} (1)/(o)+(1)/(i)=(1)/(f) \\ (1)/(i)=(1)/(f)-(1)/(o) \end{gathered}`

Solution

`\begin{gathered} (1)/(i)=(1)/(-11)-(1)/(-25) \\ i=-7.64\text{ cm} \end{gathered}`

The negative sign means that the image is virtual.

(b)

`\begin{gathered} (h)/(i)=(H)/(o) \\ h=(H)/(o)\cdot i \\ h=3.1\text{ cm}\cdot\frac{7.64\text{ cm}}{25\text{ cm}} \\ h=0.95\text{ cm } \end{gathered}`

0.95 cm - the diameter of the coin’s image

Final answer:

L-ocation: -7.64 cm

O-rientation: Inverted

S-ize: 0.95 cm

T-ype: Virtual