Question

What volume will 0.875 moles of kr occupy at stp?

Answer 1

1 mole --------- 22.4 L at ( STP )
0.875 moles ----- ?

0.875 x 22.4 / 1 => 19.6 L

hope this helps!

Answer 2

Volume = 19.6 L

Solution:

As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

Using this reference, we can calculate the volume occupied by Krypton (Ideal situation) as,

1 mole of Kr occupies = 22.4 L of Volume

So,

0.875 moles of Kr will occupy = X L of Volume

Solving for X,

X = (0.875 mol × 22.4 L) ÷ 1 mol

X = 19.6 L