Answer:
S(A) = 7
Explanation:
A ⊆B means A is a proper subset of B. That means all elements of set A are also elements of set B
S(B\A) means the set of all elements of B that are not in set A. This is given as 28
We are also given S(B) = 5.S(A)
Since A is a subset of B, S(B) = set of all elements in A and set of all elements in B but not in A
In other words
S(B) = S(A) + S(B\A)
Since S(B) = 5S(A) we get
5S(A) = S(A) + S(B\A)
5S(A) = S(A) + 28
5S(A) - S(A) = 28
4S(A) = 28
S(A) = 7