Question

A laboratory technician needs to make a 72​-liter batch of a 20​% acid solution. How can the laboratory technician combine a batch of an acid solution that is pure acid with another that is 10% to get the desired​ concentration?

Answer 1

I hope this helps you 72.20%=(72+?).10% 72.2=72+? ?=72

Answer 2

Answer: 8 L of 100% pure acid and 64 L of 10% acid must be combined

Explanation:

According to the dilution law,

`C_1V_1+C_2V_2=C_3V_3`

where,

`C_1` = concentration of pure acid solution = 100 %

`V_1` = volume of pure acid solution = x L

`C_2` = concentration of another acid solution= 10%

`V_2` = volume of another acid solution= (72-x) L

`C_3` = concentration of resulting acid solution = 20 %

`V_1` = volume of resulting acid solution = 72 L

Putting the values in the equation:

`100* x+10* (72-x)=20* 72`

`x=8L`

Therefore, the laboratory technician must take 8 L of 100% pure acid and (72-8) = 64 L of 10% acid to get 72​-liter batch of a 20​% acid solution.