Question

Can someone please help me with this math problem? Thank you!

Answer 1

To find the zeros, set y = 0

`-5(x-4)^2 +10 = 0`
Now try to isolate the (x-4)^2 term (move 10 to right side, divide by -5)

`(x-4)^2 = (-10)/(-5) = 2`
Next take square root of both sides (this cancels the square on (x-4))

`x-4 = \pm √(2)`

`x = 4 \pm √(2)`

For interpretation, x = price, y = profit
We are solving for price where profit = 0.