Question

Help me pleaseeeeeeee

Answer 1

`\begin{gathered} r=2\text{ common ratio} \\ a_n=a_1\cdot r^(n-1)_{} \\ \text{Substitute }n=4,\text{ and }r\text{ = 2} \\ a_n=a_1\cdot r^(n-1)_{} \\ a_4=2\cdot2^(4-1)_{} \\ a_4=2\cdot2^3 \\ a_4=16 \\ _{} \end{gathered}`

The first 4 terms therefore are, 2, 4, 8, 16.