283,303 views
17 votes
17 votes
36. The system of two linear equations given by:2x+4y=1 and x=-2y+1/2hasa. No solutionsb. An infinite number of solutionsc. Possibly several solutionsd. Exactly one solutione. None of the above

User Tyler Hayes
by
2.6k points

1 Answer

24 votes
24 votes

Solution:

Given:


\begin{gathered} 2x+4y=1\ldots\ldots\ldots\ldots\text{.}(1) \\ x=-2y+(1)/(2)\ldots\ldots\ldots\ldots\text{.}(2) \\ \\ R\text{ earranging equation (2);} \\ x+2y=(1)/(2) \\ \text{Multiplying the equation all through by 2;} \\ 2x+4y=1\ldots\ldots\ldots\ldots\ldots(2) \end{gathered}

Since both equations are mathematically the same, then the graph of both linear equations are shown below;

From the above graph given, the system of two linear equations has an infinite number of solutions.

The correct answer is option B.

36. The system of two linear equations given by:2x+4y=1 and x=-2y+1/2hasa. No solutionsb-example-1
User Meny
by
3.2k points