The domain of y = tan x is the set {x:x ∈ R and x ≠ (2n + 1)π/2, n ∈ z
y = secx = 1/cosx
the domain of y = secx is the set {x:x ∈ R and x ≠ (2n + 1)π/2, n ∈ z
We can see that the domains are the same. Thus, the correct option is
D. y = secx
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