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Express the product in simplest form 8/2x+8 * x^2-16/4

User Risyasin
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From formula a^2-b^2 = (a-b)(a+b) :
x^2 - 16 = (x-4)(x+4)

In 2x+8 factor out "2", you'll reach 2(x+4). So:


(8)/(2x+8) \cdot (x^2-16)/(4)=(8(x-4)(x+4))/(2(x+4) \cdot 4)= (8(x+4)(x-4))/(8(x+4))= \boxed{x-4}

(In finish you delete 8(x+4) from nominator and denominator)
User ParoX
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