Question

Write the equation of the line passing through point (-6,0) and perpendicular to y= 3/2x

Answer 1

First, let's find the slope of our line.

Remember that the product between lines that are perpendicular is -1.

This way,

`(3)/(2)\cdot m=-1\rightarrow3m=-2\rightarrow m=-(2)/(3)`

Using the slope-point form,

`y-0=-(2)/(3)(x+6)\rightarrow y=-(2)/(3)x-4`

Therefore, the line that passes through (-6,0) and that is perpendicular to y=(3/2)x is:

`y=-(2)/(3)x-4`

Answer: Option B