(5 – 8x)/ square root of -8x +5 1-(-8x + 5)^(-1/2)2-(-8x + 5)^(1/2)3-(8x - 5)^(2)4) 1/(-8x + 5)

Dahui asked Aug 26, 2023

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Dahui asked Aug 26, 2023

by Dahui

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18 votes

Given:-

$\frac{5-8x}{\sqrt[]{-8x+5}}$

To find its denominator.

So the denominator of the given function is,

$\frac{1}{\sqrt[]{-8x+5}}$

So the above expression can be written as,

$(\sqrt[]{-8x+5})^{(-(1)/(2))}$

Billrichards answered Sep 1, 2023

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