Question

A 135-g sample of a metal requires 2.50kj to change its temperature from 19.5 degrees Celsius to 100.0 degrees Celsius. What is the specific heat of this metal?

Answer 1

Answer: The specific heat of the metal is
`0.23J/g^0C`

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat absorbed=
`2.50kJ=2500J`

m= mass of substance = 135 g

c = specific heat capacity = ?

Initial temperature =
`T_i` = 19.5°C

Final temperature =
`T_f` =100.0°C

Change in temperature ,
`\Delta T=T_f-T_i=(100-19.5)^0C=80.5^0C`

Putting in the values, we get:

`2500=135* c* 80.5^0C`

`c=0.23J/g^0C`

The specific heat of the metal is
`0.23J/g^0C`