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How do you implicitly differentiate: x^3y^3-y=x
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How do you implicitly differentiate: x^3y^3-y=x

User Aleks Korovin
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x^3 y^3 - y = x
3x^2 3y^2 dy/dx = 1
dy/dx = 1/(9x^2 y^2)
User Volearix
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