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Approximate to the nearest tenth the real zeros of f(x) = –5x3 + 9x2 + 12x + 2.

answers:
The zeros are approximately 0.2, 0.7, and 2.7.
The zeros are approximately –2.7, –1.7, and 0.2.
The zeros are approximately –0.2, –0.7, and 2.7.
The zeros are approximately –0.5, –0.7, and 1.7.

2 Answers

3 votes

Answer:

the answer is C

Explanation:

User Rob Osborne
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5 votes
Correct answer is C.


-5 x^3 + 9 x^2 +12 x+ 2=(-5 x-1) \left(x^2-2 x-2\right) \\ \\\left\{-(1)/(5),1-√(3),1+√(3)\right\}\to \{-0.2,-0.732051,2.73205\}

Or check if f(0.2) = 0 to eliminate A and B.
Then check if f(-0.5) = 0 to eliminate D.
User Camilo Martin
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7.9k points