Question

2. Consider the inequality below. Which value of x is a solution to theinequality?*х2x + 39>+1X = -10x= -6x = 0x = 6

Answer 1

`\begin{gathered} (2x+3)/(9)>(x)/(3)+1 \\ (2x+3)/(9)>(x+3)/(3) \\ 3(2x+3)>9(x+3) \\ 6x+9>9x+27 \\ 6x-9x>27-9 \\ -3x>18 \\ \frac{\cancel{-3}x}{\cancel{-3}}>\frac{18}{\cancel{-3}},\text{ dividing by negative on both sides, flips the inequality} \\ x<-6 \end{gathered}`