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48.0g piece of metal is dropped into 50.0mL of water in a graduated cylinder. The water level rises to 62.4mL. What is the density of the metal?

User Jan Koch
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2 Answers

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Subtract 50 mL from 62.4 mL to get the volume of the metal. Then, divide the mass (48g) by the volume to get your density
User Vini
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V = VF - V1

V = 62.4 - 50.0

V = 12.4 mL

Density = M/V

= 48 g / 12.4 m:
= 3.87 g/mL

Hope this helps
User David Shepherd
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