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A bicycle and rider going 14 m/s approach a hill.

A bicycle and rider going 14 m/s approach a hill.-example-1
User Luke Dupin
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1 Answer

16 votes
16 votes
Answer:

The bicycle will be 10m above the staring level when it finally stops

Step-by-step explanation:

The speed of the bicycle, v = 14 m/s

The combined mass of the bicycle and rider, m = 86 kg

Acceleration due to gravity, g = 9.8 m/s²

The kinetic energy = 0.5mv²

Kinetic Energy = 0.5 x 86 x 14²

Kinetic Energy = 8428 Joules

The height of the hill = h

The potential energy = mgh

As the rider coasts up the hill, the kinetic energy is converted to potential energy

Kinetic energy = Potential energy

8428 = mgh

8428 = 86(9.8)h

8428 = 842.8h

h = 8428/842.8

h = 10 m

The bicycle will be 10m above the staring level when it finally stops

User Rogn
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